name = 'p. diddy', which output of the following choices is NOT correct
A、name[:] 'p. diddy'
B、name.title() 'diddy'
C、name.index('dd') 5
D、name.split('.') ['p', ' diddy']
发布时间:2025-03-15 11:27:18
A、name[:] 'p. diddy'
B、name.title() 'diddy'
C、name.index('dd') 5
D、name.split('.') ['p', ' diddy']