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1.jeep dʒi:p]
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2.#include int main(void){int a[10],*p=a,i; for(i=0;i a[i]=2*i; p=a+6; printf("%d %d",*p,*a); return
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3.复利现值系数是( )A、P·i·nB、(1 i·n)C、(F/P,i,n)D、(P/F,i,n)
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4.复利终值系数是( )A、(P/F, i ,n)B、(F/P,i,n)C、(1 i·n)D、P·i·n
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5.设年金为A, 计息期为n, 利息率为i,则先付年金现值的计算公式为( )A、P=A*(P/A,i,n)*(1 i)B、P=A* (P/A,i,n)C、P=A* ((P/A,i,n-1) 1)
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6.#includemain(){ int a[20],*p[5],i;for(i=0;i<20;++i)a[i]=i;for(i=0;i<5;++i)p[i]=&a[i*4];for(
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7.I stood staring at the jeep as it bumped and __________ over the uneven ground of the hilly road.
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8.设年利率为i,现存入p元,若计复利,n年后可得钱数为( )A、p﹡(1 i﹡n) ﻩﻩB、p﹡(i 1)nC、p﹡(1 i)﹡nﻩﻩ ﻩﻩD、p﹡(i n)
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9.jeep
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10.jeep: