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- 医师定期考核
答案:
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1.B.-2yf(r,y)CyDf(ry)
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2.2.设z=2f(xy),其中函数f可微则 A 2yf'(r, y)B.-2yf'(r,y)D
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3.B. df(x. y)d.C. dy. f(ry)dxD. dyf(r, y)d.
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4.)ry m- y= 0
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5.(3) f(x, y,z)= ry y = l,x y z= 0.
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6.(2)l ry dirdy, D: r y2 s2.r
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7.y r yT V y r
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8.公式(∀x)[P(x)∧Q(x,A)→(∃y)[E(x,y)∨S(y)]]中,∀x的辖域为(),∃y的辖域为()A.P(x); R(x, y)B.P(x) ꓥ Q(x, A); R(x, y)C.P(x
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9.RY
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10.m,R-j y=R(x y