printf ("sum=%d
printf ("sum=%d
发布时间：2025-03-15 05:42:50
请在 下方输入 要搜索的题目：
推荐参考答案 (
由 快搜搜题库 官方老师解答 )
答案：count=%d\n"
相关试题
- 1.printf ("sum=%d
- 2.int w = 0; void fun() { w++; printf("w = %d ", w); } main() { int w = 5; w++; printf("w = %d ", w); fun
- 100);else printf("%d", a<=100);}">3.请写出以下程序的输出结果是#includemain(){int a=100;if(a>100) printf("%d", a>100);else printf("%d", a<=100);}
-
4.试写出以下程序段的运行结果#include
main( ) { int a=88,b=89; printf("%d %d",a,b); printf("%d,%d",a,b - 5.SUM
-
6.#include
int main(){ int n; int i, sum = 0; scanf("%d",&n); for(i=1; (1) - 7.float sum=1while (i<=50)sumt=1/( float)⊥;i ,i ;printf{"1 1/2 1/4 … 1/50=f\n",aum)
- 100); else printf("%d\n", a">8.请写出以下程序的输出结果是 #include main() {int a=100; if(a>100) printf("%d\n", a>100); else printf("%d\n", a
- 100); else printf("%d", a<=100">9.【填空题】请写出以下程序的输出结果是 #include main() {int a=100; if(a>100) printf("%d", a>100); else printf("%d", a<=100
- 10.程序代码如下：#include Int main(){ intA,b; printf("please input a and b:\n"); scanf("%d%d",&a,&b)
