t=0:pil/50:2*pi;5.*cos(t) 4polar(t, r)title(" rho=5*cos \theta 4)(2)t=-pi/3: pi/50: pi/3r=5.*(sin(t).^2)./cos(t);polar(t,r
t=0:pil/50:2*pi;5.*cos(t) 4polar(t, r)title(" rho=5*cos \theta 4)(2)t=-pi/3: pi/50: pi/3r=5.*(sin(t).^2)./cos(t);polar(t,r
发布时间：2025-06-21 18:32:52
