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1.N je j , k N m 20,其它k
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2.0,其它AX(A) =〈jeJ ,k = m% je一计,k = N — m0,其它化
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3.k=n%10:f(n==i**i j*j*j k*k*kcout<
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4.B i=k/m, j=k%mC i=k/n,k%onD = m, jon
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5.func(int n){ int i,j,k;i=n/100; j=n/10-i*10; k=n%10;if((i*100 j*10 k)==(i*i*i j*j*j k*k*k))return n;return
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6.for(j=0;jfor(k=0;ka[j][k]=j*k;A.O(m2)B.O(n2)C.O(m*n)D.O(m n)
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7.(n m) k=n (m k)被称之为加法的__
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8.2)k=0;for (i=1: i=n: i Or
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9.下面代码的输出结果是 for n in range(100,200): i = n // j = n // % k = n % if n == i ** 3 + j ** 3 + k ** print(
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10.对任意整数m, n和k, 若gcd(m, n) = 1, m|k且n|k,则mn|k.