def pw (x:Int) : Int = {if (x == 0) 1 else 2*pw(x-1) } , 求 pw(5) ?
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1.def pw (x:Int) : Int = {if (x == 0) 1 else 2*pw(x-1) } , 求 pw(5) ?
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2.baltimore county pw
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3.PW的作用包括
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4.下面关于函数的声明正确的是( ) ①int fun1(int x=0, int y); ②int fun2(int x=0, int y=0); ③int fun3(int x, y=0); ④int
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5.有以下定义和语句:struct workers{ int num;char name[20],c;struct{int day,month,year;}s;};struct workers w,*pw;
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6.fun(int x){int y=0;static int z=3;z ; y;return(x y z);}main( ){int I,x=2;for(i=0;i
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7.main() { int x = 2, y = -1, z = 2; if (x < y) if (y < 0) z = 0; else z + = 1; printf("%d ",z); }
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8.下列程序的输出结果是 :#include void f(int v, int w) { int t; t = v; v = w; w = t;}int main(){ int x
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9.执行以下程序段后,x的值为0,y的值为1。
int x, y;
if (x = 0) y = 0;
else y = 1;
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10.7、分解因式xA、(x 2 1)(x 2 -1)B、(x-1)(x 1)(x 2 1)C、(x 1) 2 (x-1) 2D、(x-1)(x 1) 3