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1.st=[(,),]st[]=(st)结果是
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2.st=[["a","b"],"c"]st[0][1]='d'print(len(st),st)结果是
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3.def f(st): st.append('x') return stst=['a']st=f(st)print(st)结果是
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4.st={"name":"xxx","emails":["a@123.com","b@123.com"],"age":20}del st["emails"][0]st["emails"].append("
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st[]=st={:,:}
f(st)
(st">5.f(st):
st[]=st={:,:}
f(st)
(st
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6.(1) ST=1 ST=0 ST= B2)[10111111
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7.列表st定义为: st
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8./"brekfɑ:st/ B./"breikfəst/ C./"brekfəst/ D./"breikfɑ:st/
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9.列表st定义为:
st
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10.△st ystB.β△st ystC.△st βystD.β( △st yst)