由(1.4-3)式推导(1.4-4)式。
由(1.4-3)式推导(1.4-4)式。
发布时间：2025-06-06 15:00:16
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答案：证明:[tex=4.857x1.786]fzrKTZhw0Cw1Xr4gWfOWga9pE8ZZL3rRAEqQDibkJDK/Tdun1dOjk6rkQYSL2M64[/tex][tex=4.286x2.214]kpWGGgGx4yzoNYO7SllrsadvB0x2osvDIioegDic1P7+9+oEMRg6ExC2gFSBXUme1E8h8cRQSwcTY9NYgox+xb/bIVMOi8sSSKDcFztA+Fqr74USG44cOLTb+Y3qwFu8[/tex] (1.4-3)[br][/br][tex=10.714x2.643]BqL4ES9sL1cQnow47oQQNkNEPsW2Xnqsa3tISPO/vxaXidmv6z3wPXtH4OoPF1UyXttLZEGS+6BP0UsjefMPcYTGQ+6inSLx6nFU7wSPySnEAIEhWvHiVJwmnzBVAtsDfMVZr+RgiaPsuk1XlzQf9/5OIB/5S2IdTSi5ERd3X6E=[/tex] (1.4-4)取一六方体元, 中心在[tex=3.214x1.357]8sXOVKPrSl7odQ08YRvxPw==[/tex]体积为[tex=6.286x1.214]2QpyeGQi/cWonuSbJXtHSp7W+ogTYAIUUAv+AlAVGB3pMmE+c0NFM8PlP+ROz49D[/tex], 下面是六个面的中心位置, 面积和法向[br][/br][img=675x331]17cfa817225fe36.png[/img]求包围体积 [tex=1.429x1.0]0bkfymlTas3DLnU2c89wKA==[/tex]的封闭面的通量, 得[tex=19.143x2.929]WmvpBf98XjlgECVyA6V0pUK0/Bcnc3If8//BUviYJXipbqC7NK99CaEwtu8vHb1gvXOry48PvfYMURgqg2GccEOzNLm8aSQ8b1dagoIdSJ7XwA+ysWKwAF03+vi8EfpfVgE9sXybDJg2yePoEraYmQE52d1QNcg0br3yEw/ccaXsViMhktb/mEcuY34fkp8BzU7l+m1SKbTHPfpqxngPTkEpBPYPlzTdVhk4WNpftBY+5Owv01gRubHvVSFatY00KjcY2SwdruJIe2yOC2mvcIfyxk+nwudzBJjsW6ezACo=[/tex][br][/br][tex=20.214x2.357]Y9y8ZXxLfgcER1t1nD4py6vspyN2WY3/H+8b8c9Ly+Vbu/ahuFESTA0/oJDijwBKFrf8LBDHWj4Z7nM+7EDohTGgT9eMU7HzOOmVDfjj3bX2Wp8r4CCyNXLMOJcphRXa/gWJAgRAsAWPL/T3F5O6p7V0HDK0HKTxqsRPr1/BNycilhh1qC3M5QhSfzqtVceNlJnGZWiVP3sVeSPrQjzVcMFYeTjF126tDn+bSD3xNGHQ/T0Dlqho1T8vfkfwHWxH8YCbd3aezqoITWzgpDuo2mwFiJHvrGrX5KkrURbqmf176y++85X0vk6msZCapz7QPgqhu4cfOvtOsfuszohuIg==[/tex]
