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输入10个学生的成绩,输出最低分数。

发布时间：2025-06-26 11:52:07

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答案：解:#include <>void main(){int i;double score,min;printf(“请输入 10个学生成绩:\n”);scanf(“%lf”,&score);min=score;

年信息查询 2.元旦是星期几信息查 3. 程序结束\n”);printf(“请输入年份:\n”);scanf(“%d”,&year);printf(“请选择功能:\n”);scanf(“%d”,&number);if(number==1){ year=legal(year);leapyear(year);}if(number==2){ week=judgeweeknumber(year);judgeweekchinese(week);}if(number==3)return;}int legal(int y){ if(y<0)do {printf(“请重新输入一个年份:”);scanf(“%d”,&y);} while(y<0);return y;}void leapyear(int y){if(y%4==0&&y%100!=0||y%400==0)printf(“%d是闰年\n”,y);elseprintf(“%d不是闰年\n”,y);}int judgeweeknumber(int y){ int week;week=(y (y-1)/4-(y-1)/100 (y-1)/400)%7;return week;}void judgeweekchinese(int week){ switch(week){ case 0: printf(“星期天”); break;case 1: printf(“星期一”); break;case 2: printf(“星期二”); break;case 3: printf(“星期三”); break;case 4: printf(“星期四”); break;case 5: printf(“星期五”); break;case 6: printf(“星期六”); break;}}*14.输入n、x,计算xn 输出。要求定义一个递归函数计算xn 。解:#include<>double mypow(double x,int n){double y=1;if (n>0)return(x*mypow(x,n-1));elseif (n<0) return(1/x*mypow(x,n 1));else return 1;}void main(){ double x;int n;printf(“请输入x n:\n”);scanf("%lf%d",&x,&n);printf("%f\n",mypow(x,n));}*15.数列的第1、2项为1,此后各项为前两项之和。编制求数列中任何一项值的递归函数。解:此数列为1、1、2、3、5、8、13 ……。#include<>int f(int n){ if (n==1||n==2)return (1);elsereturn (f(n-1) f(n-2));}void main(){ int n;while(scanf("%d",&n),n<0);printf("数列第%d项为:%d",n,f(n));}习题 5