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- 通信工程师考试
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1.积蓄jÿxù
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2.#include int main(){ int x[]={1,3,5,7,2,4,6,0},i,j,k; for(i=0;i<3;i++) for (j=2;j>=i;j--)
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3.已知x(n)就是实序列,x(n)得4点DFT为X(k)=[1,-j,-1,j],则X(4-k)为( )A、[1,-j,-1,j]B、[1,j,-1,-j]C、[j,-1,-j,1]D、[-1,j,
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4.一.(1) X (2) V (3) X (4) J (5) V (6) J (7) J (8) X (9) X (10( )
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5.int i,j, x=0;for(i1i.≤ni )for (j=i l; i<=n; j X ;
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6.int i, j, x=0;Eor (i=l; i
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7.(j/c/s;j/x)司机买________________
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8.#include void main(){void fun(int, int);int i = 2, x = 5, j = 7;fun(j, 6);printf("i=%d;j=%d;
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9.int i, j, x=0;Eor (i=l; i(n; i )for (j=i l; i<=n; j X ;
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10.已知x[k]是实序列,x[k]的4点DFT为X[m]={1,-j,-1,j},则X[4-m]为( )