由下列数据确定NO(g)的△fHmӨ为( )2NH3(g)→N2(g)+3H2(g) ,△H1Ө=92.2 kJ/molH2(g) +1/2O2(g) →H2O(g), △H2Ө=-241.82 kJ/mol4NH3(g) +5O2(g) →4NO(g)+6 H2O(g), △H3Ө=-905.48 kJ/mol
A、90.26 kJ/mol;
B、44.14 kJ/mol;
C、228.58kJ/mol ;
D、361 kJ/mol
发布时间:2025-03-17 12:29:12